####################################################### # 12 YEAR Ayelet DAILY-RASHI-YOMI CYCLE # # April 17th, 2002 # # Rashis 1359-1361 Of 7800 (17.4%) # # # # VISIT THE RASHI YOMI ARCHIVES # # ----------------------------- # # http://www.RashiYomi.Com/calendar.htm # # # # Reprinted with permission from Rashi-is-Simple, # # (c) 1999-2002, RashiYomi Inc., Dr Hendel President # # Permission to reprint with this header PROVIDED # # it is not printed for profit # # # # WARNING: READ with COURIER 10 (Fixed width) FONTS# # # ####################################################### |
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EXAMPLE: Ex38-24b 1 KIKAR=3000 SHEKEL (Currency):1 SHEKEL=2 BEKA EXAMPLE: Ex38-26a 1 KIKAR=3000 SHEKEL (Currency):1 SHEKEL=2 BEKA EXAMPLE: Ex38-26b 1 KIKAR=3000 SHEKEL (Currency):1 SHEKEL=2 BEKA BACKGROUND ---------- Ex38 lists - The Total silver accumulated for the Mishkan - How many people donated THE TEXT Ex38-24:26 ------------------- The Total Silver donated was 100 KIKAR and 1775 SHEKEL... The donation amount was 1 BEKAH per PERSON There were 603,550 PEOPLE THE RASHI --------- Some simple algebra allows us to combine these facts to obtain the value of the currency units used ONE KIKAR = 3,000 SHEKEL ONE SHEKEL= 2 BEKAH Upon multiplying out we see 3000*2 + 1775*2 = 603,550 THE LIST -------- The list below lists these verses, supporting verses, and the algebraic equations needed to solve the above REFERENCES ---------- The Rashi Rule used is called SPREADSHEETS A reference is http://www.RashiYomi.com/h13n8.htm Or http://www.Rashiyomi.com/ex38-24b.htm | |||
AMOUNT | AMOUNT OF WHAT UNIT | ASSUMPTION | ALGEBRAIC EQUATION |
100 | KIKAR | K = Sx*1 | |
1775 | SHEKEL | ||
1 | BEKAH | S=2B*2 | |
603,550 | PEOPLE | 1P = 1B*2 | 100K+1775S=603550B*3 |
COMMENTS | |||
*1 We assume that -- the each KIKAR (K) was equal to an UNKNOWN amount (X) of SHEKEL, S *2 Ex38-26 States [There was 1 BEKAH donated for Each Person] Ex30-13 states [Each person will donate HALF A SHEKEL] Hence I conclude that ONE SHEKEL = 2 BEKAH (S=2B) or equivalantly that each person donated 1 Bekah *3 We can solve this equation as follows 100K+1775S = 100 Sx + 1775S by Substitution K=Sx 100 Sx + 1775S =S(100x+1775) (by Factoring) Thus S(100x+1775) = 603550(S/2) = 301775(By Expansion) Dividing both sides by S we obtain 100X+1775= 301775 Subtracting 1775 from both sides we obtain 100X = 300000 Dividing both sides by 100 we obtain X = 3000 In other words there were 3000 Shekels Per KIKAR*10 *11 -------------------------- LONGER FOOTNOTES -------------------- *10 This amount (3000 @ Kikar) is also consistent with with the fact that the SHekel units for GOld, Silver and copper --- 730, 1775, 2400 -- never exceed 3000 (Since then we would regroup can carry) *11 Interestingly the five rules used to solve this system of equations - Factoring - substitution - Expansion - subtraction (from both sides) - Division (of both sides) are exactly the 5 rules needed to solve any equation in 1 unknown |